Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average by 8 runs. His new average is:

  • A. 20
  • B. 21
  • C. 28
  • D. 32

Let’s denote Ajit’s average for the first 9 innings as

A. The average is calculated by dividing the total runs by the number of innings.

The total runs from the first 9 innings would be

9A (average multiplied by the number of innings).

Now, in the 10th inning, he scores 100 runs, so the new total runs become

9A+100.

The new average is then calculated by dividing the new total runs by the total number of innings (10 innings now).

So, the new average (

B) is given by:

 

B=9A+10010

It is mentioned that the new average is 8 runs more than the previous average (

A).

 

B=A+8

Now, we can set up an equation and solve for

A:

 

A+8=9A+10010

To solve for

A, you can follow these steps:

Multiply both sides of the equation by 10 to eliminate the fraction:

 

10(A+8)=9A+100

Distribute the 10 on the left side:

 

10A+80=9A+100

Subtract
9A

 

 

from both sides:

 

A+80=100

Subtract 80 from both sides:

 

A=20

So, Ajit’s average for the first 9 innings (

A) is 20 runs. Now, his new average after the 10th inning is

A+8=20+8=28 runs.

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